![]() ![]() > A = reshape (A, 2, 3) Share.Create mask of 3D matrix with zeros function. > A (lZeros) = Finally, reshape the array to your desired size using the built in reshape command. then use this logical array to index into A and delete these zeros. matrix_FA=zeros (SSf,SSa) Ln_total=0 while Ln_totalA 2:A->P if Type=1 if randA 2:A->P if Type=1 if rand> lZeros = A=0.Simply assign the lower right element to zero, even if that element does not exist yet, and it will pad everything up to there with … matrix_FA=zeros (SSf,SSa) Ln_total=0 while Ln_totalA 2:A->P if Type=1 if randA 2:A->P if Type=1 if randA 2:A->P if Type=1 if randA 2:A->P if Type=1 if rand0, and then depending on difference between two indexes (from the find function) and depending on the first right and left non-zero number (from the original matrix), I calculate numbers between these two non-zero numbers and replace zeroes with these …d = padarray (b, ,0) This code is padding a row above and a row below the matrix but i just want it below the 2x3 matrix.(because MATLAB doesn't actually know how many zeros it … This is because MATLAB doesn't attempt to "naturally" resize the outputs any other way. ![]() ans = 1×10 logical array.Calling nonzeros on the matrix a will return a vector of elements. matrix_FA=zeros (SSf,SSa) Ln_total=0 while Ln_totalA 2:A->P if Type=1 if rand 0) % Only operate on dimension 1. ![]() padded = zeros (256,256) data = rand (16,16) padded (1:16,1:16) = data So, this doesn't actually answer your question, but I think it answers the use case you gave. Matlab automatically pads with zeros if you assign something to an element outside of the original size. B = ones (5,7) % all dimensions larger than A.5 Answers. If you are sure the new dimensions are larger, this will also work: Theme. To pad an matrix A with zeros to match a larger or same-sized array B, you can use this: newA (1:size (A,1), 1:size (A,2)) = A. 95 views (last 30 days) Show older comments. Create mask of 3D matrix with zeros function. ![]()
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